Bootstrap Dynamic Autocomplete search using Typeahead JS

By Hardik Savani November 5, 2023 Category : PHP Bootstrap HTML jQuery Typeahead JS

In this post i am going to show you how to add dynamically Autocomplete using typeahead dynamic. In this post i give you full example that way you can run this example easily in your project. after run this example you can see output like bellow preview.

First we will create ajax.html file for html layout in this file i added jquery and Bootstrap Typeahead code. When you write on input box then you can find Dynamic Autocomplete search using ajax requiest. So, first create aja.html file and copy bellow code.

ajax.html

<html lang="en">
<head>
    <title>Bootstrap Typeahead with Ajax Example</title>  
    <link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet">
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.js"></script>
    <script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-3-typeahead/4.0.1/bootstrap3-typeahead.min.js"></script>  
</head>
<body>

<div class="row">
	<div class="col-md-12 text-center">
		<br/>
		<h1>Search Dynamic Autocomplete using Bootstrap Typeahead JS</h1>	
			<input class="typeahead form-control" style="margin:0px auto;width:300px;" type="text">
	</div>
</div>

<script type="text/javascript">

	$('input.typeahead').typeahead({
	    source:  function (query, process) {
        return $.get('/ajaxpro.php', { query: query }, function (data) {
        		console.log(data);
        		data = $.parseJSON(data);
	            return process(data);
	        });
	    }
	});

</script>
</body>
</html>

Ok, now we need to create another page for getting json data by ajax requiest. So create another page ajaxpro.php file and copy bellow code.

ajaxpro.php

Read Also: How to Install Bootstrap in Laravel?
<?php
	
	define (DB_USER, "root");
	define (DB_PASSWORD, "root");
	define (DB_DATABASE, "learn");
	define (DB_HOST, "localhost");
	$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);

	$sql = "SELECT items.title FROM items 
			WHERE title LIKE '%".$_GET['query']."%'
			LIMIT 10"; 
	$result = $mysqli->query($sql);
	
	$json = [];
	while($row = $result->fetch_assoc()){
	     $json[] = $row['title'];
	}

	echo json_encode($json);

Try this.....

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